a beaker contains a liquid of density rho up to a height of h with acceleration due to gravity as g.calculate the pressure at the free surface of the liquid.calulate the pressure at the base of the liquid
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Answered by
11
At the surface=atmospheric pressure .(101325pascal)
P at bottom =rho.g.h+atmospheric pressure
P at bottom =rho.g.h+atmospheric pressure
Answered by
21
Pressure = hpg
In this case g= a+g
Therefore, P= hp(g+a).
Hope it helps!!
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