Question

A beaker contains water up to a height h, and
kerosene of height h above water so that the
total height of(water+kerosene) is (ha + h).
Refractive index of water is u, and that of
kerosene is Ma. The apparent shift in the
position of the bottom of the beaker wher
viewed from above is :​

Answer 1

The apparent shift in the bottom of the beaker will be equal to the sum of the individual shifts caused by the kerosene and water mediums.

Shift because of water = h

1

(1−

μ

1

1

)

Shift because of kerosene = h

2

(1−

μ

2

1

)

Hence, the net shift will be, h

1

(1−

μ

1

1

) + h

2

(1−

μ

2

1

)

Answer 2

Answer:

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