Question

if x=2 is zeros of equation x^2+3√2kx+2=0 find value of k​

Answer 1

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Answer 2

$p(x) = {x}^{2} + 3 \sqrt{2} kx + 2 = 0$

$given \: that \: x = 2 \: is \: zero \: of \: p(x)$

$p( - 2) = {( - 2)}^{2} + 3 \sqrt{2} \times ( - 2)k + 2 = 0 \\ p( - 2) = 4 - 6 \sqrt{2} k + 2 = 0 \\ - 6 \sqrt{2}k = - 6 \\ k = \frac{ - 6}{ - 6 \sqrt{2} } \\ k = \frac{1}{ \sqrt{2} } = \frac{1}{ {2}^{ \frac{1}{2} } } = {2}^{ \frac{ - 1}{2} }$