A beaker is filled with water as shown. the bottom surface of the beaker is a concave mirror
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Answer:
A beaker is filled with water as shown.
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Explanation:
Let R be the radius of curvature of the lens.
Considering refraction of the object from the first surface,
v23−−434=R23−34
Now this image at v acts as object for the next refraction,
Hence v11−v23=−R1−23
Now for final image to be obtained again at the same position, the image and the object for the reflection from this mirror must be at the same place.
Hence the object at v should be at the center o curvature of the mirror,
v1=−R
Using this in the above relation gives, R=5m
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