Question

A beam has a triangular cross-section having base 40 mm and altitude 60 mm. If this section is subjected to a shear force of 36000 n, the maximum shear stress in the cross-section would be

Answer 1

Answer:

don't ask maths question because first u have to solve by urself

Answer 2

The maximum shear stress in the cross-section is 45 $\bold{N/mm^2}$

Given:

Base = b = 40 mm

Altitude = h = 60 mm

Shear force = 36000 N

To find:

Maximum shear stress = ?

Formula used:

$\bold{Average \ shear \ stress = \tau_{av}=\frac{Shear \ Force}{bh/2}}$

$\bold{Maximum \ shear \ stress = 1.5 \times \tau_{av}}$

Solution:

Now, the average shear stress is:

$\bold{\tau_{av}=\frac{36000}{\frac{40\times60}{2}}}$

$\bold{\tau_{av}=\frac{36000\times 2}{40\times60}}$

$\bold{\therefore \tau_{av}=30 \ N/mm^2}$

Now, the maximum shear stress is:

$\bold{Maximum \ shear \ stress = 1.5 \times \tau_{av}}$

$\bold{Maximum \ shear \ stress = 1.5 \times 30}$

$\bold{\therefore Maximum \ shear \ stress = 45 \ N/mm^2}$