A beam having photon of energy 480 k eV is incident on a foil of aluminum. If the photonis scattered at 45°, then calculate the energy of the recoil electron.
Answers
Answer:
beam having photon of energy 480 k eV is incident on a foil of aluminum. If the photon is scattered at 45°, then calculate the energy of the recoil electron.
Explanation:
Well actually for dawn scattered it 100 and five degrees relative to the incident direction. Uh and the foot on scatters from a free electron addressed. So 115° is the scattering angle party in. Yeah, violent of scattered photon is 0.3 to zero nanometers. So prevalent of scattered foot on land of prime equals zero point 3 to 0 nanometers. And 0.3-0 nm is equal to 0.32 zero multiplied by 10 to the power -9 m. Well, no, let's calculate incident photons travel And uh we'll find lambda. Lambda. Lambda is uh the violent of incident put on. We know that change in babbling equals It's divided by mass of electron times speed of flight into 1 -1 go sign feta. And in this case theta equals 115 degrees. Therefore each divided by massive electron times a speed of light into 1 -4 Sign of 115°. And this gives us delta lambda. Change in Dublin uh equals h divided by mass of electron times speed of flight into one Uh plus zero four. And then we have change involvement equals 1.4. Multiply by 6.63. Multiply by 10 to the power of -34 divided by Mass of electron is 9.1, multiplied by 10 to the power -31 and then the speed of light is three. Multiplying returned to the power eight m/s and therefore change in Maryland is equal to 3.4 3.4 multiplied by 10 to the power minus 12 minus 12 m. Okay, well change involvement can be written is a land of prime minus lambda and therefore lambda, which is the development of incident for dawn equals um left the prime minus change in gravel. And and this gives us lender equals lender. Crime is a zero point 0.3-0 0.3-0. multiplying they tend to devour uh minus nine minus. Then we have changed environment and change environment is 3.4 multiply by 10 to the power minus 12 m and therefore lambda equals uh, lender equals 3.17. 3.17 multiply. We tend to the power -10 m -10 meters. And this can be written is lambda equals 0.0.317 nanometers. The lambda equals 0.3 17 nanometers. So let's sold part B. Energy of a photon is given by HF N H F. Can be written is Hc divided by lambda. Now let's calculate the energy of incident photo on um will calculate energy of incident for dawn, incident fortune. What time let's plug in? The values Equals 6.63 multiplied by 10 to the power -34 multiply by three. Multiply. We tend to the power it divided by Um Linda is 0.317. multiplied by 10 to the power -9. And this gives us um 62 point 74 Multiply by 10 to the power -17 jewels -17 jewels. Now let's convert this into electron walls, 62.74. multiplied by 10 to the power -17 jewels. Uh uh his 62.74 multiplied by 10 to the power minus 17. Divided by 1.6 Multiple Library 10 to the power -19 -19 Electron Walls. And this gives us um This gives us 39.2 39 points to multiply with 10 to the power to electron volts. And this can be written as 3.92 kg electron balls. So energy of incident for dawn is 3.92 kg electron volts. Now let's calculate energy of scattered photons, energy of scattered proton, scattered energy of scattered photons. Well, energy is given by hc divided by lambda prime. Let's plug in the values H is 6.63. Multiply with 10 to the power -34. Multiply. The speed of light is three. Multiply. We tend to live our eight Divided by land. The crime is 0.0.3- zero. Multiply. We tend to the power -9. And this gives us E equals 62 points 62.16. Multiply by 10 to the power minus 17 jules. Let's express this number in electron votes Therefore equals 62.16. multiplied by 10 to the par -17 divided by Uh divided by 1.6, multiplied by 10 to the power -19. And this gives us 38.8 28.8 multiply by tend to be power to electron walt. And this can be written is 3.88 3.88 kg electron volt. So energy have scattered for dawn is 3.88 kg electron volt. Now let's calculate the kinetic energy of recoil electron part C. Well, we know that um kinetic energy equals um kinetic energy equals Hc, divided by lambda, XC, divided by lambda minus hc, divided by lender prime. So kinetic energy equals etc. divided by λ is three 92 kg electron holes minus eight C. Divided by lambda prime is 3.88 kg electron balls. And therefore kinetic energy of recoil electron equals 0.4 kg electron volt. And this can be written is 40 electron volts.