a beam of light converges at a point P. Now a lens is placed in the path of the convergent beam 12cm from P. At what point does the beam converge if the lens is (a) a convex lens of focal length 20cm,and (b) a concave lens of focal length 16cm.
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(a). According to the given case, object is virtual, u=+12 cm
The focal length of the convex lens is f=+20 cm.
Using lens equation,
v
1
−
u
1
=
f
1
v
1
−
12
1
=
20
1
v=7.5 cm
(b). Now the focal length of the concave lens, f=−16 cm
v
1
−
u
1
=
f
1
v
1
−
12
1
=
−16
1
v=48 cm
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