Question

A beam of light is converged at a point 9 cm behind (i) a converging lens of focal length 12 cm, and
(ii) a diverging lens of focal length 15 cm. Find the image position in each case.
Ans: (i) 5.1 cm (ii) 22.5 cm
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Answer 1

Answer:

5.1 ,22.5

Explanation:

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Answer 2

Answer:

1. 5.1
2. 22.5

Explanation:

Here,u=-9

f=12

v=?

Then

1/f=1/v + 1/u

1/v = 1 /u - 1 /f

1/v = 1/(-9) -1/12

1/v = (-9 - 12)/(12*9)

v = - 108/21

= 5.1