A beam of light passes from air into a substance X . If the angle of incidence be 72 degree and the angle of refraction be 40 degree , calculate the refractive index of substance X ?
Answers
Answered by
64
Given:
Angle of incidence i= 72°
=sin 72° = 0.951
and angle of refraction = r= 40
=sin 40° = 0.642
Therefore, refractive index=sin i/sin r
Refractive index =n= sin 72°/sin 40°
=0.951/0.642
=1.48
∴ Refractive index of material is 1.48
Angle of incidence i= 72°
=sin 72° = 0.951
and angle of refraction = r= 40
=sin 40° = 0.642
Therefore, refractive index=sin i/sin r
Refractive index =n= sin 72°/sin 40°
=0.951/0.642
=1.48
∴ Refractive index of material is 1.48
Answered by
9
Answer:
Explanation:
Since, Sin i / Sin r =n
where n is constant of proportionality
So,
Sin 72 / Sin 40 = n
0.951 / 0.642= n
n= 1.48
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