Question

A beam of light passes from air into a substance X . If the angle of incidence be 72 degree and the angle of refraction be 40 degree , calculate the refractive index of substance X ?

Answer 1

Given:
Angle of incidence i= 72°
=sin 72° = 0.951
and angle of refraction = r= 40
=sin 40° = 0.642
Therefore, refractive index=sin i/sin r
Refractive index =n= sin 72°/sin 40°
=0.951/0.642
=1.48

∴ Refractive index of material is 1.48

Answer 2

Answer:

Explanation:

Since, Sin i / Sin r =n

where n is constant of proportionality

So,

Sin 72 / Sin 40 = n

0.951 / 0.642= n

n= 1.48