Question

A beg contain 6 red ball, 8green balls, 9 yellow balls and 12 pink balls. A ball is taken out atrandom from the bag then find the probability of getting
A. A pink ball
B. Neither a yellow ball nor a red ball

Answer 1

Data:

6 red balls

8 green balls

9 yellow balls

12 pink balls

35 total balls

A)

Pink Ball/ Total Balls

= 12/35

B)

35-9-6/35

20/35

= 4/7

Answer 2

s = 35
A= 12
p (A)= 12/35
= 0.34
B= 0
p (B)= 0/35
= 0