Math, asked by adityajain1808, 1 year ago

A beggar is having 50 coins with an amount of Rs.15 in denominations of 25 paise and 50 paise. how many 25 paise coins are there with the beggar?

aryanppp: please post the question properly in the fractional form as asked because the language you have written is not understandable

adityajain1808: That's literally the exact question. I've copied it as it is. There are no fractions in the questions.

Answers

Answered by brainlyuttkarsh

Let the number of 50 paise coins be x and number of 25 paise coins be y
Given that the man has 50 paise and 25 paise coins worth Rs 5
That is (0.50x + 0.25y) = 5 → (1)
Given that (0.50x = 0.25y)
⇒ 2x = y
Hence equation (1) becomes,
(0.50x + 0.25 × 2x) = 5
⇒ (0.50x + 0.50x) = 5
⇒ x = 5
Hence y = 10
Therefore there are five 25 paise coins and ten 50 paise coins.

adityajain1808: how is 0.50x=0.25y?

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