Math, asked by ajayrathuar4580, 1 year ago

A bell rings every 18 minutes. a second bell rings every 24 minutes. a third bell rings every 32 minutes. if all the three bells rings at the same time at 8 o'clock in the morning, at what other time will they all ring together?

Answers

Answered by Sourasnata
29
Hope it will help you.

Attachments:
Answered by mysticd
8

Answer:

 \red { All \: bells \: ring \: together \:at }

 \green { = 12.48 \:p.m }

Step-by-step explanation:

Given

A bell rings every 18 minutes. a second bell rings every 24 minutes. a third bell rings every 32 minutes.

Find the LCM of 18 , 24 and 32.

2 | 18, 24, 32

___________

2 | 9 , 12 , 16

___________

2 | 9 , 6 , 8

___________

3 | 9 , 3 , 4

___________

*** 3 , 1 , 4

 LCM( 18, 24 , 32 ) = 2\times 2\times 2 \times 3 \times 3 \times 4 \\= 288 \: minutes\\= \frac{288}{60} hours\\= 4\:hours \:48 \: minutes

 If\: all \the \: bells \: rings \:at \: the \: same \\time \: at \: 8\: O' clock \: in \:the \: morning,\:then \\they \:ring \: all \: together \\at \: ( 8+4\:hours \:48\: minutes ) = 12.48 \:p.m

Therefore.,

 \red { All \: bells \: ring \: together \:at }

 \green { = 12.48 \:p.m }

•••♪

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