A benz car is travelling with a speed 360 kmph its brakes can produce an acceleration 20 m/s find the distance before it comes to rest and the distance travelled in the last second
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360kmph=100m/s
using third equation of motion
0=10000-2*20*x
so x=250m
time taken to travel 250m=
0=100-20t=t=5 seconds
distance travelled in 4 seconds=400-160=240m
so distance travelled in last second=250-240=10m
I HOPE IT WILL HELP YOU.
using third equation of motion
0=10000-2*20*x
so x=250m
time taken to travel 250m=
0=100-20t=t=5 seconds
distance travelled in 4 seconds=400-160=240m
so distance travelled in last second=250-240=10m
I HOPE IT WILL HELP YOU.
champion360:
please mark as brainliest
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