Question

A bhs b/w mysuru and bengaluru passes at 100km , 160km, and 220km points at 10:30 am, 11:30am and 1:30 pm. Find the average spped of the bus during each of the following intervals to kmph and m/s. a. 10:30am to 11:30pm b. 11:30am to 1:30 pm c. 10:30 am to 1:30pm

Answer 1

Distance travelled by driver in 2hours

= 300×40100= 120 km

Distance to be covered in 2 hours

= 300−120 = 180 km .

Required speed = 1802 = 90 km/ h

Required difference = 90−1202= 30 km/hr.

So increase speed = 30 km/hr

I hope you are understand My solution