Question

a bicnvex lens of radii 5 cm of 5 diopter power then what is the refractive index of the lens​

Answer 1

Answer:

$\frac{27}{2}$

Explanation:

For equi biconvex lens,

$\frac{1}{f } = (u - 1) \frac{2}{r}$

$5 = (u - 1) \frac{2}{5}$

$u - 1 = \frac{25}{2}$

$u = \frac{25}{2} + 1$

$u = \frac{25 + 2}{2}$

$u = \frac{27}{2}$

Answer 2

take okkkkk

Explanation: