A bicocave lens has focal length half the radiusof curvature of either surface. What is the refractive index of the material lens
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Explanation:
A bicocave lens has focal length half the radiusof curvature of either surface. What is the refractive index of the material lens
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Answer:
Hence, the refractive index = n = 2
Explanation:
We know that,
Focal length = Radius of curvature / 2
➡ f = R/2
For a thin convex lens we have the relation ,
1/f = (μ - 1)(1/R1 - 1/R2) f
Focal length = R/2 μ
Refractive index R1, R2 the radii of curvature of both the surfaces
Here R1 = R and R2 = -R Therefore 1/f = (μ - 1)(1/R - 1/(-R))
2/R = (μ - 1)(2/R) (μ - 1) = 1
⇒ μ = 2
Hence, the refractive index = n = 2
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