Physics, asked by gogoianir02, 9 months ago

A bicocave lens has focal length half the radiusof curvature of either surface. What is the refractive index of the material lens

Answers

Answered by vuluvalasubhash
0

Explanation:

A bicocave lens has focal length half the radiusof curvature of either surface. What is the refractive index of the material lens

1

Answered by Anonymous
5

Answer:

Hence, the refractive index = n = 2

Explanation:

We know that,

Focal length = Radius of curvature / 2

➡ f = R/2

For a thin convex lens we have the relation ,

1/f = (μ - 1)(1/R1 - 1/R2) f

Focal length = R/2 μ

Refractive index R1, R2 the radii of curvature of both the surfaces

Here R1 = R and R2 = -R Therefore 1/f = (μ - 1)(1/R - 1/(-R))

2/R = (μ - 1)(2/R) (μ - 1) = 1

⇒ μ = 2

Hence, the refractive index = n = 2

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