Question

A bicycle costs $50 to hire for the first day and $40 for each extra day. If C(k) is the cost of hiring the bicycle for k days, the recurrence relation is:

Select one:

a. C(1)=40, C(k)=c(k-1)+40

b. C(1)=50, C(k)=c(k-1)+50

c. C(1)=50, C(k)=c(k-1)+40

d. C(1)=40, C(k)=c(k-1)+50​

Answer 1

SOLUTION

GIVEN

A bicycle costs $ 50 to hire for the first day and $ 40 for each extra day. If C(k) is the cost of hiring the bicycle for k days, the recurrence relation is:

Select one:

a. C(1)=40, C(k)=c(k-1)+40

b. C(1)=50, C(k)=c(k-1)+50

c. C(1)=50, C(k)=c(k-1)+40

d. C(1)=40, C(k)=c(k-1)+50

EVALUATION

Here it is given that A bicycle costs $ 50 to hire for the first day and $ 40 for each extra day.

Now C(k) is the cost of hiring the bicycle for k days

So by the given condition C(1) = 50

Again C(k) = C(k-1) + 40

Hence the required recurrence relation is

C(1) = 50 , C(k) = C(k-1) + 40

FINAL ANSWER

So the correct option is

c. C(1) = 50 , C(k) = C(k-1) + 40

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ solve the recarency relation ar-7ar-1+10ar-2=2r,a0=0,and a1=6

https://brainly.in/question/2163198

2. Solve the recurrence relation s(k)-10s(k-1)+9s(k-2)=0 with s(0)=3,s(1)=11.

https://brainly.in/question/23772288

Answer 2

SOLUTION

GIVEN

A bicycle costs $ 50 to hire for the first day and $ 40 for each extra day. If C(k) is the cost of hiring the bicycle for k days, the recurrence relation is:

Select one:

a. C(1)=40, C(k)=c(k-1)+40

b. C(1)=50, C(k)=c(k-1)+50

c. C(1)=50, C(k)=c(k-1)+40

d. C(1)=40, C(k)=c(k-1)+50

EVALUATION

Here it is given that A bicycle costs $ 50 to hire for the first day and $ 40 for each extra day.

Now C(k) is the cost of hiring the bicycle for k days

So by the given condition C(1) = 50

Again C(k) = C(k-1) + 40

Hence the required recurrence relation is

C(1) = 50 , C(k) = C(k-1) + 40

FINAL ANSWER

So the correct option is

c. C(1) = 50 , C(k) = C(k-1) + 40

━━━━━━━━━━━━━━━━