Question

A bicycle initially moving with a velocity 5 m/s, accelerates for 5 seconds at a rate of 2 m/s^2. What will be the final velocity. ​

Answer 1

Answer:

Initial velocity of the bicycle (u) = 5 m/s

Acceleration (a) = 2 m/s^2

Time (t) = 5 sec

Let the final velocity of the bicycle be v.

Now, using first equation of the motion:

$v = u + at \\ v = 5 + 2 \times 5 \\ v = 15 \: m \: per \: sec$

Answer 2

FINAL VELOCITY IS 15 m/s.

Given:

• Initial velocity (u) = 5 m/s
• Acceleration (a) = 2 m/s²
• Time (t) = 5 sec

To find:

• Final velocity (v) ?

Calculation:

Since the acceleration (as given in question) is constant, we can apply the EQUATIONS OF KINEMATICS:

$v = u + at$

$\implies \: v = 5 + (2 \times 5)$

$\implies \: v = 5 + 10$

$\implies \: v = 15 \: m {s}^{ - 1}$

So, final velocity is 15 m/s.