Question

A bike accelerates uniformly from 20 kmh¹ to 36 kmh-¹ in 5 s. Calculate (i) the acceleration and (ii) the distance covered by the car in that time.​

Answer 1

Answer:

$Acceleration=TimeChange in Velocity </p><p></p><p>Change in Velocity = 36−18=18km/h=5m/s </p><p></p><p>Time=5 Seconds</p><p></p><p>Acceleration =55=1m/s2 </p><p></p><p>Equation of motion can be given as:</p><p></p><p>s=ut+(21)at2</p><p></p><p>u=18km/h=5m/s </p><p></p><p>t=5s</p><p></p><p>a=1m/s2 </p><p></p><p>s=(5×5)+(21×1×5×5)</p><p></p><p>s=25+12.5</p><p></p><p>s=37.5m</p><p></p><p>$

Explanation:

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