A bike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4 m. Determine the acceleration of the bike.
Answers
Answered by
1
Explanation:
The kinematic equation of motion we need is
v
2
=
u
2
+
2
a
s
, where:
v
= final velocity (
m
s
−
1
)
u
= initial velocity (
m
s
−
1
)
a
= acceleration (
m
s
−
2
)
s
= distance traveled (
m
)
a
=
v
2
−
u
2
2
s
=
7.1
2
−
0
2
2
⋅
35.4
=
50.41
70.8
=
0.71200565
≈
0.71
m
s
−
2
Answered by
2
The answer is a = 0.712 m/s2
process:
Given:
vi = 0 m/s
vf = 7.10 m/s
d = 35.4 m
To Find:
a = ??
vf2 = vi2 + 2*a*d
(7.10 m/s)2 = (0 m/s)2 + 2*(a)*(35.4 m)
50.4 m2/s2 = (0 m/s)2 + (70.8 m)*a
(50.4 m2/s2)/(70.8 m) = a
a = 0.712 m/s2
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