Question

A bike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4 m. Determine the acceleration of the bike.​

Answer 1

Explanation:

The kinematic equation of motion we need is

v

2

=

u

2

+

2

a

s

, where:

v

= final velocity (

m

s

−

1

)

u

= initial velocity (

m

s

−

1

)

a

= acceleration (

m

s

−

2

)

s

= distance traveled (

m

)

a

=

v

2

−

u

2

2

s

=

7.1

2

−

0

2

2

⋅

35.4

=

50.41

70.8

=

0.71200565

≈

0.71

m

s

−

2

Answer 2

The answer is a = 0.712 m/s2

process:

Given:

vi = 0 m/s

vf = 7.10 m/s

d = 35.4 m

To Find:

a = ??

vf2 = vi2 + 2*a*d

(7.10 m/s)2 = (0 m/s)2 + 2*(a)*(35.4 m)

50.4 m2/s2 = (0 m/s)2 + (70.8 m)*a

(50.4 m2/s2)/(70.8 m) = a

a = 0.712 m/s2