Question

A bike accelerates uniformly from rest to a speed of 7.10m/s over a distance of 35.4 m. Determine the acceleration of the car .

Answer 1

Displacement (s): 35.4m
Initial speed (u) :7.10m/s
Final speed (v):0 since it comes at rest
V^2=U^2+2as
0=(7.1)^2+2•a•35.4
a= -0.712
Hope This Helps!!

Answer 2

Given:

uniformly accelerates from rest - u = 0m/s

final velocity - v = 7.10m/s

Distance covered - s =

To Find:

acceleration of the car - a =?

Solution:

Formula used:

• Newton's third law of motion equation - v² - u² = 2as

Applying the above formula:

v² - u² = 2as

(7.10)² - (0)² = 2 × a × 35.4

50.41 - 0 = 2 × a × 35.4

50.41 = 70.8a

a = 50.41/70.8

a = 0.712 m/s²

Hence, the acceleration of the car = 0.712 m/s²