A bike acquires the velocity of 36km/hr in 10s just after the start. It then takes 20s to stop. Find acceleration in 2 cases. Please Explain with Answer
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In first case
u=0 v=36km/h=10m/s t=10sec
a=v-u/t
=10-0/10=1m/s^2
Second case
u=10m/sec v=0 t=20sec
a=v-u/t
=0-10/20=-0.5m/s^2
u=0 v=36km/h=10m/s t=10sec
a=v-u/t
=10-0/10=1m/s^2
Second case
u=10m/sec v=0 t=20sec
a=v-u/t
=0-10/20=-0.5m/s^2
anubhavsil137:
ur answer is wrong man
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I think the answer is helpful for you
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