Math, asked by haidyfathy2004, 6 months ago

A bike and skate shop rents bikes for $21 per day and pairs of skates for $20 per day. To remain viable, the shop needs to make at least $362 per day from bike and skate rentals combined. If they rent twice as many bikes as they do pairs of skates, what is the least number of pairs of skates they need to rent each day to make their minimum? 4 5 6

Answers

Answered by wakiyabegum
0

Answer:

Let x be the amount of bikes and y be the amount of skates.

So then they make 21x from bikes and 20y from skates

The total amount they make has to be AT LEAST ( ≥ ) $362. So,

21x+20y≥362

twice as many bikes as pairs of skates mean

x=2y

Substitute back into the inequality to get

21(2y)+20y≥362

Answered by dolemagar
0

Step-by-step explanation:

let x be the number of skates(in pair) and twice skates = bikes= 2x

we have

2x(21)+20(x)= 362

42x+20x = 362

x= 362/62

= 5.83

so the least number of skates (in pair) they need to rent is not less than 5.8. And since skates cannot be in fraction.

Thus 6 is the answer.

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