a bike is moving with a velocity of 90 km/he after applying brake it stop in 5 seconds calculate the force applied by the break mass of motorcycle and rider is 200 kg
Answers
Answered by
3
v = 0
u=90 * 1000/3600
u= 25m/s
a = v-u/t
a = 0-25/5
a = -5m/s^2
f = ma
f = 200*-25
f = -5000 N
I hope it will help u
u=90 * 1000/3600
u= 25m/s
a = v-u/t
a = 0-25/5
a = -5m/s^2
f = ma
f = 200*-25
f = -5000 N
I hope it will help u
Anonymous:
the force applied would be positive you have to state that force is positive but direction is opposite
force cannot be negative
yeah your r right
Answered by
2
v = u + at
90 kmph = (90*1000)/3600
= 25 m/s
v = u+at
25 m/s = 0 +( a×5s)
25/5s m/s = 5a/5s
5 ms^-2 = a
F = ma
m =200 kg
a = 5 ms^-2
F = 200 kg × 5 ms^-2
= 1000 N
ans is,
1000 N
gm
y? am i wrong?
ok
he
are talking to me or piyush
kya
what does it mean?
by Kya
sorryfor that im srilankam so i think its hindi
ok
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