Question

A bike is travelling at a uniform speed of 90 k/h. Calculate the distance cover in 5 second​

Answer 1

Answer:

Correct option is

A

45

Let original speed =xkm/hr

⇒ Time taken to travel =

x

90

hr

⇒ New speed =(x+15)km/hr

⇒ Time taken to travel =

x+15

90

hr

∴

x

90

=

x+15

90

+

2

1

⇒

x

90

−

x+15

90

=

2

1

⇒ 90(

x

1

−

x+15

1

)=

2

1

⇒

x(x+15)

x+15−x

=

180

1

⇒ 15×180=x(x+15)

⇒ 2700=x

2

+15x

⇒ x

2

+15x−2700=0

⇒ x

2

+60x−45x−2700=0

⇒ x(x+60)−45(x+60)=0

⇒ (x+60)(x−45)=0

Speed can not be negative.

∴ The original speed of the train is 45km/hr

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Answer 2

Answer:

125 m

Explanation:

We have,

=> Speed (s) = 90 Km/h

=> Time (t) = 5 s

To find,

=> Distance

Solution,

=> 90 Km/h

=> 90 × 5/18 m/s

=> 25 m/s

Using the formula,

=> Distance = speed × time

>> Distance = 25 × 5

>> Distance = 125 m

∴ The distance covered in 5 seconds is 125 m.