Question

A bike moving along a straight road covers 35meters in the 4th seconds and 40meters in 5thseconds.what is its initial velocity and its acceleration.(If the acceleration is assuming to be uniform)

Answer 1

Increase in distance per second is (20 – 12)/ 2 = 4 m/s

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Distance covered during 2nd second = 12= 3*4

Distance covered during 4th second =20=5*4

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Distance covered during 6th second =28=7*4 ( after 5 seconds )

Distance covered during 9th second =40 = 10*4

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Distance covered in 4 second after 5 th second is

4 times the average of 28 and 40

(28+40)*4 / 2=136 m