Question

A bike moving at a speed of 10m/s stopped by applying break which produce of 0.5m/s how much distance will be covered by bike before it stop

Answer 1

Using third equation of motion(when acceleration is opposite to direction of velocity)

2a s=v^2 - u^2

But we have to find distance(s)

so,

s=v^2-u^2/2a

s=0-10X10/2X0.5

s=100/1

s=100 meter Answer