A bike moving with velocity of 36 km/h comes to the rest on the application of brakes in 5s.calculate the retardation of the bike in m/s2.
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Answered by
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u=36×5/18=10m/s
v=0
t=5
v=u+at
0=10+(-a)×5
a=10×5
a=50m/s^2
v=0
t=5
v=u+at
0=10+(-a)×5
a=10×5
a=50m/s^2
Answered by
0
Answer:
-2m/s^2
Explanation:
u = 36km/h × 5/18 = 10m/s
t = 5sec.
v = 0m/s
v = u + at
0 = 10 + a × 5
-10 = 5a
-10/5 = a
-2 = a
a = -2m/s^2
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