Question

A bike staring from rest has a uniform acceleration of 0.2 m/s2 . Calculate the speed of the bike after 2.5 minutes.

Answer 1

Answer:

Speed of bike after 150 sec = 30 m/s

Step-by-step explanation:

Given:

• Initial velocity of bike = u = 0
• Acceleration of bike = a = 0.2 m/s²
• Time = 2.5 minutes = 150 sec

To find:

• Speed of bike after 150 sec = v = ?

Solution:

The equation of motion that connects all the given data is the First Equation of motion.

v = u + at

⇒ v = 0 + 0.2(150)

⇒ v = 0 + 30

⇒ v = 30 m/s

∴ The speed of bike after 150 sec = 30 m/s

Answer 2

Answer:

$\underline{\purple{\ddot{\Mathsdude}}}$

Given:-

• Initial velocity =u=0
• Acceleration of the given bike = 0.2m/s^2
• Time = 2.5minutes =150sec

To prove :-

• Speed of bike after 2.5 minutes .

Explanation :-

• Here we should use first equation of motion

1. v=u+at

Now applying the values,

• v=0+0.2 (150)
• v=0+30
• v=30m/s

Therefore, the speed of bike after 150sec is 30m/s

Hope it helps u mate .

Thank you .