A bike start with speed of 20km/h and it's acceleration is 10km/h for 30 minute find final velocity of bike
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Speed or initial velocity (u) 20kmph
20x 5/18 =50/9 m/s =5.55 m/s
Acceleration(a)= 10km/hr^2 (10 x 1000)/
3600 x 3600= 1/1296 m/s^2
Time (t) 30 minutes =1800 seconds
Final velocity(V) = u at
v =50/9 + 1800/1296
=> v=6.94 m/s
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Speed or initial velocity (u)= 20kmph = 20× 5/18 = 50/9 m/s = 5.55 m/s
Acceleration(a)= 10km/hr^2 = (10 × 1000)/3600 × 3600 = 1/1296 m/s^2
Time(t) = 30 minutes = 1800 seconds
Final velocity(v) = u + at
=> v = 50/9 + 1800/1296
=> v = 6.94 m/s
Hope it helps, if it does,
plz mark as BRAINLIEST....
Acceleration(a)= 10km/hr^2 = (10 × 1000)/3600 × 3600 = 1/1296 m/s^2
Time(t) = 30 minutes = 1800 seconds
Final velocity(v) = u + at
=> v = 50/9 + 1800/1296
=> v = 6.94 m/s
Hope it helps, if it does,
plz mark as BRAINLIEST....
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