A metal wire when bent in the form of an equilateral triangle of the
largest area, encloses an area of 484^1/3 cm2. If the same wire is bent into
the form of a circle of the largest area, find the area of a circle.
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Answer:
2117.7 cm²
Step-by-step explanation:
Length of wire = L
Side length of equilateral triangle = a
Perimeter of equilateral triangle = 3a
3a = L
a = L/3
Area of equilateral triangle = (√3/4)a²
484^(1/3) = (√3/4)a²
484^(1/3) = (√3/4)(L/3)²
484^(1/3) = (√3/4)L/9
L = [9 × 484^(1/3)] / (√3/4)
Circumference of circle = L
2πr = L
r = L / (2π)
= [(9 × 484^(1/3)) / (√3/4)] / (2π)
= 25.97 cm
Area of circle = πr²
= 3.14 × (25.97 cm)²
= 2117.7 cm²
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