Physics, asked by Avnishdh, 11 months ago

A bike travels with a speed of 40m\s claculate acceleration of the bike to travel 200m distance in 4s and what is the final velocity of bike?​

Answers

Answered by Anonymous
1

Hii i am girl

s= ut +at^2/2

200 = 160 + 16a

a = 40/16 = 10/4= 2.5m/s^2

v =u + at

v= 40 + 2.5*4

v= 40 + 10 = 50 m/s

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Answered by mamtag1802
0

s=ut+(at^2)/2

200=160+8a

40=8a

a=5m/s^2

v=u+at

v=40+5*4

v=60m/s

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