Question

A biker starts from rest and increases his velocity at the rate of 3 (m/s)²for 4 seconds. What is the velocity of the biker after 4 seconds? ​

Answer 1

Answer:

u = 0m/s

a = 3m/s^2

t = 4s

v = ?

v = u + at

v = 0m/s + 3m/s^2 * 4s

v = 12m/s

hope it helps

Answer 2

Therefore the velocity of the biker after 4 seconds is 12 m/s.

Given:

Initial velocity = u = 0 m/s

Increase in velocity at the rate of 3 m/s² for 4 seconds.

To Find:

The velocity of the biker after 4 seconds.

Solution:

The given question can be answered as shown below.

Given that,

Initial velocity = u = 0 m/s

Acceleration = Rate of change of velocity = a = 3 m/s²

Time taken = t = 4 seconds

⇒ Acceleration = ( Change in velocity ) / ( Time taken )

⇒ Acceleration = a = ( v - u ) / t

Where v is the final velocity after 4 seconds.

⇒ a = ( v - 0 ) / 4 = 3

⇒ v = 12

Therefore the velocity of the biker after 4 seconds is 12 m/s.

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