Question

A bill For Rs 8500 on 25th April For
5 months was discounted on 17 July
@ 5.P.a Find the discounted value
of the bill​

Answer 1

Step-by-step explanation:

Given that mean,

μ

= 63.6, standard deviation,

σ

= 2.5 and sample size,

n

= 100

The respective Z-score with sample mean,

¯

X

= 63 is

Z

=

¯

X

−

μ

σ

/

√

n

Z

=

63

−

63.6

2.5

/

√

100

Z

= -2.4

Now, we use normal tables to find the probability greater than -2.4

P (Z > -2.4) = 1 - 0.0082

P (Z > -2.4) = 0.9918