Physics, asked by nandanadinesh20000, 8 months ago

The density of a cube is measured by measuring its mass and length of its sides.if the maximum error in the measurement of mass and lengths are 3% and 2% respectively, the maximum error in the measurement of density would be​

Answers

Answered by zahaansajid
0

Density = Mass/Volume

Let density = D

mass = M

volume = V

∆D/D = ∆M/M + ∆V/V

Since, Volume = V = L³

∆V/V = 3∆L/L = 3×2 = 6%

∆M/M = 3%

Hence, the maximum error in measuring density

= ∆D/D = ∆M/M + ∆V/V = 3 + 6 = 9%

Therefore the maximum error in measuring the density is 9%

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Answered by JohnFerrari
0

Answer:9%

Explanation: density = mass/volume (m/l^3)

Error in mass ∆m/m = 3%

Error in l^3 = 3×∆l/l = 3×2 = 6%

Therefore , total error = 3% + 6% = 9%

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