A binary tree t has n leaf nodes. The number of nodes of degree 2 in t is
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here is your answer ↙️↙️☺️☺️✌️✌️
In a "m-ary" tree. the number of total nodes are given by
N=mi+1
Where i: Number of internal nodes
Also, in a tree, N=I+L where L=number of leaf nodes
Here m=2
So, N=2i+1.
2i+1=i+l
L=I+1 The number of leaves are 1 plus the number of internal nodes in binary tree.
Here, given L=n, subsitute above and we will get I=n-1.
Hope this helps you mate ☺️☺️⭐⭐✌️✌️✅✅✅
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