A biock of mass 0.50 kg is moving with a
speed of 2.00 m/s on a smooth surface. It
strikes another mas 1.00 kg and then they
move together as a single body. The
energy loss during the collision is
(AIEEE-2008
1) 0.16 J
2) 1.00 J
3) 0.67 J
4) 0.34 J
*
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Answer:
R.E.F image
By momentum conservation
0.5×2=1.5×v
v=
3
2
m/sec
Initial Energy =
2
1
×0.5×(2)
2
=1 joule .
Final Energy =
2
1
×1.5×(
3
2
)
2
=1/3 joule .
Loss= Initial-Final
=1−
3
1
=
3
2
=0.67J
Explanation:
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