Question

A biomolecule contains 2% magnesium by mass. The minimum molecular mass of biomolecule is

Answer 1

Dear Students,

◆ Answer -

1200 g/mol

◆ Explanation -

Atomic mass of Mg is 24.

Given smallest biomolecule must contain at least 1 atom of Mg.

Minimum molecular mass of biomolecule is calculated as -

Minimum mass of biomolecule = Atomic mass of Mg × 100 / Percentage of Mg

M = 50 × 24

M = 1200 g/mol

Therefore, least possible molecular mass of given biomolecule is 1200 g/mol.

Hope this helps you understand..

Answer 2

Answer:

The minimum molecular mass of biomolecule is 1200u

Explanation:

Atomic mass of Mg is 24.

Mass of Mg/Total mass of Biomolecule*100 =2

Taking at least one Mg molecule

⇒$\frac{24.3}{M_{B} }$ *100 = 2

⇒$M_{B}$ =$\frac{24.3*100}{2}$

⇒$M_{B}$ = 1215≈ 1200u

Therefore, least possible molecular mass of given biomolecule is 1200u.

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