Question

A bird flies at 9.2 m high with a velocity of 10 m / s. Find the ratio of its potential energy to its kinetic energy.

Answer 1

Potential energy = mgh = 10×9.2m = 92m

Kinetic energy = (1/2)mv^2 = 1/2 m ×100 = 50m

Ratio
92:50
46:25

Answer 2

Answer: The ratio of the potential energy and kinetic energy is 49:25.

Explanation:

Given that,

Height h = 9.2 m

Velocity v = 10 m/s

We know that,

The potential energy is define as:

$P.E = mgh$

The kinetic energy is define as:

$K.E = \dfrac{1}{2}mv^2$

Where, m = mass of the object

V = velocity of object

H= height

g = acceleration due to gravity

The ratio of the potential energy and the kinetic energy is

$\dfrac{P.E}{K.E}= \dfrac{mgh}{\dfrac{1}{2}mv^2}$

$\dfrac{P.E}{K.E}= \dfrac{2gh}{v^2}$

$\dfrac{P.E}{K.E}=\dfrac{2\times9.8\times9.2}{10\times10}$

$\dfrac{P.E}{K.E}=\dfrac{1127}{625}$

$\dfrac{P.E}{K.E}=\dfrac{49}{25}$

Hence, The ratio of the potential energy and kinetic energy is 49:25.