Question

A bird is flying at the height 3m above the river surface while a fish is 4m below the surface. At what depth would the fish appear to the bird ? At what height the bird would appear to the fish ?
$\sf\red{(given \ n_{wa} \ = \ \dfrac{4}{3})}$​

Answer 1

Answer: The correct answers are 8 m and 7 m.

Explanation:

The expression for the refractive index in terms of apparent depth in air is as follows;

\mu =\frac{Apparent depth in air}{Real depth in air}μ=

Realdepthinair

Apparentdepthinair

Put \mu=\frac{4}{3}μ=

3

4

and Real depth in air= 3 m.

\frac{4}{3} =\frac{Apparent depth in air}{3}

3

4

=

3

Apparentdepthinair

Apparent depth in air=4 mApparentdepthinair=4m

The fish would see the bird at 4+4 = 8 m.

The bird would see the fish at 3 m + 4 m= 7 m.

Therefore, the fish would appear to the bird at depth of 8 m. The bird would appear to fish at the height of 7 m.

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Answer 2

Answer:

Correct answer is 7m and 8m

Explanation:

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