Question

A bird is flying down vertically towards the surface of water in a pond with constant. There is a fish inside the water.if that fish exactly vertically below the bird then the bird will appear to the fish to be :
a.farther away than its actual distance
b.closer than its actual distance
c.moving faster than its actual speed
d.moving slower than its actual speed.
which of the four options are true? How can you prove it ?
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Answer 1

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★ fish is in denser medium w.r.t bird

and speed of light is higher in rare medium as compared to denser medium

V = Vb + mu. Vb

★ As we know

D (apparent) = D (actuall )/ R.I

here , observer is fish and object is bird

● in this case D(apparent) > D (actual)

means,

Bird will appear farther away from its actual distance.

D (apparent ) = mu × D (actual )
★ Option a is correct !

Both option a and c is correct

happy to help !

:)

Answer 2

Answer:

my answer is option A and C

I hope it it is helpful to you