If two a and b sets have 99 elements .proved that a×b have 99×99 elements.
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HEY DEAR ... ✌️
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Here's , ur answer :-
A and b having 99 elements in common .
Then number of elements common to each of the sets a × b and b × a = 99 × 99
= (99)² = 9801 .
Actually, you can see choose 99 elements which are common to both a and b in 99 ways separately in both the cases .
And when you will multiple these you will get the same number of elements e.g., a × b = (99)² and b × a = (99)²
So, tbe answer should be 99² = 9801
HOPE , IT HELPS ... ✌️
______________________
______________________
Here's , ur answer :-
A and b having 99 elements in common .
Then number of elements common to each of the sets a × b and b × a = 99 × 99
= (99)² = 9801 .
Actually, you can see choose 99 elements which are common to both a and b in 99 ways separately in both the cases .
And when you will multiple these you will get the same number of elements e.g., a × b = (99)² and b × a = (99)²
So, tbe answer should be 99² = 9801
HOPE , IT HELPS ... ✌️
Answered by
0
Answer A and b having 99 elements in common .
Then number of elements common to each of the sets a × b and b × a = 99 × 99
= (99)² = 9801 .
Actually, you can see choose 99 elements which are common to both a and b in 99 ways separately in both the cases .
And when you will multiple these you will get the same number of elements e.g., a × b = (99)² and b × a = (99)²
So, tbe answer should be 99² = 9801
hope this helps
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