Question

A bird is sitting in a wire cage hanging from the spring balance.Let the reading of the spring balance be w1.If the bird flies about inside the cage the reading of the spring balance w2.Then w1 and w2 are

Answer 1

There are two cases are possible to answer this question.

case 1 : when the cage is air tight.

for the bird to stay in the air, the wings must push down on the air under the cage. when the cage is air tight, the air exerts an equal force on the floor of the cage. so,the net force down on the scale will remain constant.

e.g.,$W_1=W_2$

case 2 : when the cage is not air tight

when the cage is not air tight, the air will move down and horizontal, then air doesn't exert an equal force on the floor of the cage. The force down will be less than the weight of the bird.

so, $W_1>W_2$

Answer 2

W1 > W2 is the answer...