A rack has 5 different pair of shoes , the number of ways of selecting 4 shoes of no complete pair
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There are 80 ways of selecting 4 shoes of no complete pair.
Step-by-step explanation:
Given,
Number of pairs = 5
So,
Total shoes = 10
Total possibilities of choosing 4 pairs of shoes = 10 * 8 * 6 * 4 = 1940
Possibilities of arranging the above pairs = 4 * 3 * 2 * 1 = 4!
Now,
The number of ways of selecting 4 shoes of no complete pair = Total possibilities of choosing 4 pairs of shoes/Possibilities of arranging the pairs
= 1940/4!
= 10 * 8 * 6 * 4/4 * 3 * 2 * 1
= 80
Thus, there are 80 ways of selecting 4 shoes of no complete pair.
Learn more: Permutation and combination
brainly.in/question/6153952
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