Math, asked by ROSHANS5584, 1 year ago

A rack has 5 different pair of shoes , the number of ways of selecting 4 shoes of no complete pair

Answers

Answered by JackelineCasarez
0

There are 80 ways of selecting 4 shoes of no complete pair.

Step-by-step explanation:

Given,

Number of pairs = 5

So,

Total shoes = 10

Total possibilities of choosing 4 pairs of shoes = 10 * 8 * 6 * 4 = 1940

Possibilities of arranging the above pairs = 4 * 3 * 2 * 1 = 4!

Now,

The number of ways of selecting 4 shoes of no complete pair = Total possibilities of choosing 4 pairs of shoes/Possibilities of arranging the pairs

= 1940/4!

= 10 * 8 * 6 * 4/4 * 3 * 2 * 1

= 80

Thus, there are 80 ways of selecting 4 shoes of no complete pair.

Learn more: Permutation and combination

brainly.in/question/6153952

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