Question

a bird is travelling vertically towards surface of the water in a pond with constant speed and there is a fish inside pond and how the bird will appear to fish​

Answer 1

Answer:

speed of that is equal to the speed odf going down

Answer 2

Answer:

the fish is under water, so if the real height of bird is h m above the surface the fish will see it at h’ such that  

real height/apparent height = refractive index of water =3/4 = g(mu)a  

h/ h’ = 3/4 so the speed dh/dt / dh’/dt = 3/4 ,  

v(bird)/ v’(as seen by fish) = 3/4  

so the velocity  seen by fish =dh’/dt = (4/3 ) * dh/dt  

= (4/3 )* V m/s = which is more then bird constant speed of v