Question

A bird moves in such a way that it has a displacement of 12 m towards east, 5 m towards north and 9m vertically upwards. Find the magnitude of its displacement.
pls answer this...​

Answer 1

Answer:To find the magnitude of displacement..

1) consider the axis, it follows..

=> 12 m on x - axis

=> 5 m on y - axis

=> 9 m on z - axis.

Now since the angle in each case made is 90° with other respective axis.

So..

Magnitude of displacement will be

Explanation:

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Answer 2

Answer:5sqrt10

Explanation:

As in all cases the bird moves 90 degrees from the initial vector therefore

The magnitude of the displacement is

|displacement| =sqrt (12^2+5^2+9^2)

= sqrt(144+25+81)

=sqrt(250)

= Sqrt(5×5×5×2)

=5sqrt (10)