Question

a bird moves in such a way that it has a displacement of 12m towards east 5m towards north and 9m verticaly upwards find the magnitude of its displacement

Answer 1

To find the magnitude of displacement..

1) consider the axis, it follows..

=> 12 m on x - axis

=> 5 m on y - axis

=> 9 m on z - axis.

Now since the angle in each case made is 90° with other respective axis.

So..

Magnitude of displacement will be

$= > |a| = \bf\sqrt{ {x}^{2} + {y}^{2} + {z}^{2} } \\ \\ = > |a| = \sqrt{ {12}^{2} + {9}^{2} + {5}^{2} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{144 + 81 + 25} = \sqrt{250} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 5 \sqrt{10} \: \: m$
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Answer 2

Answer:

5√10

Explanation:

Hope you understand by seeing above image