Question

A bivalent metal has the ml equivalent weight 12 .The molecular weight of its oxide will be

Answer 1

Answer:40

Explanation:

eq mass = molecular mass/n factor

12=molecular mass /2

mol mass =24.. which is Mg

oxide will be MgO

therefore mol mass of metal oxide = 24+16 =40

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Answer 2

Answer: 40 grams

Explanation:

Equivalent mass of a metal is defined as the mass which combines with 8 gram of oxygen or 35.5 grams of chlorine or 1 gram of hydrogen.

Given:

equivalent mass of metal = 12

valency of metal (n) = 2 (bivalent)

Equivalent weight is calculated by dividing the molecular weight by n factor.  

${\text{Molecular weight}}={\text{Equivalent weight}}\times {n}$

${\text{Molecular weight}}={12\times 2}=24g$

12 g of metal  combine with = 8 gram of oxygen

So 24 gram of metal will combine with =$\frac{8}{12}\times 24= 16g$ of oxygen

Molar mass of oxide= molecular mass of metal + molecular mass of oxygen = 24g + 16 g = 40 g

Thus  molecular weight of its oxide will be 40 grams