A bivalent metal has the ml equivalent weight 12 .The molecular weight of its oxide will be
Answers
Answer:40
Explanation:
eq mass = molecular mass/n factor
12=molecular mass /2
mol mass =24.. which is Mg
oxide will be MgO
therefore mol mass of metal oxide = 24+16 =40
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Answer: 40 grams
Explanation:
Equivalent mass of a metal is defined as the mass which combines with 8 gram of oxygen or 35.5 grams of chlorine or 1 gram of hydrogen.
Given:
equivalent mass of metal = 12
valency of metal (n) = 2 (bivalent)
Equivalent weight is calculated by dividing the molecular weight by n factor.
12 g of metal combine with = 8 gram of oxygen
So 24 gram of metal will combine with = of oxygen
Molar mass of oxide= molecular mass of metal + molecular mass of oxygen = 24g + 16 g = 40 g
Thus molecular weight of its oxide will be 40 grams