A black body of 2500k emits radiation calculate the wavelength
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Hey.
Here is the answer.
Wien's displacement law states that the spectral radiance of black body radiation per unit wavelength, peaks at the wavelength λmax given by:
λmax = b / T
where T is the absolute temperature in kelvins. b is a constant of proportionalitycalled Wien's displacement constant.
b ≈ 2900 μm·K
So, as T = 2500 K
so, λmax = 2900 μm·K/ 2500 K
= 1.16 μm
Thanks.
Here is the answer.
Wien's displacement law states that the spectral radiance of black body radiation per unit wavelength, peaks at the wavelength λmax given by:
λmax = b / T
where T is the absolute temperature in kelvins. b is a constant of proportionalitycalled Wien's displacement constant.
b ≈ 2900 μm·K
So, as T = 2500 K
so, λmax = 2900 μm·K/ 2500 K
= 1.16 μm
Thanks.
Answered by
0
All objects with a temperature above absolute zero (0 K, -273.15 oC) emit energy in the form of electromagnetic radiation. A blackbody is a theoretical or model body which absorbs all radiation falling on it, reflecting or transmitting none.
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