Question

Ab is a segment point p is on perpendicular bisector of segment ab such that length of ap exceed length of ab by 7cm if perimeter of triangle abp is 38cm find the sides of triangle abp

Answer 1

perimeter=x+x+7+x+7
38=3x+14
x=8
so side of triangle are 8,15,15

Answer 2

Answer:

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Step-by-step explanation:

 l (BP) = l (AP) = y [By perpendicular bisector theorem]

As per first condition,

y = x + 7

∴ – x + y = 7 .......eq. no. (1)

As per the second condition,

Perimeter of ∆ABP = 38

∴ x + y + y = 38

∴  x + 2y = 38 ......(2)

Adding (1) and (2),

- x + y = 7

x + 2y = 38

    3y = 45

∴ y = 45/3

∴ y = 15

Substituting y = 15 in equation (2)

∴ x + 2y = 38

∴ x + 2(15) = 38

∴ x + 30 = 38

∴ x = 38 – 30

∴ x = 8

∴l (AB) = 8 cm, l (BP) = l (AP) = 15 cm.

The length of sides of ∆ ABP are 8 cm, 15 cm and 15 cm.